VII:
Fair Division Quick Summary
Elements of a Fair Division Problem 1. A set of N
players: P1 , P2 , . . . , PN
2. A set of goods, S
The problem is to divide the set S into N shares (s1
, s2 , . . . , sN) so that each player gets a fair
share of S.
A fair share is any share that, in the opinion of the player
receiving it, has a value that is at least 1/N of the total value of the set
of goods, S.
(N is the number of players.)
A fair division scheme is a set of rules that, when properly
applied, produces a fair division of the objects to be divided.
We expect any fair division scheme to satisfy the following
conditions:
The procedure is decisive. If the rules are followed, a
fair division is assured.
The procedure is internal to the players. It requires
no outside intervention.
Players have no knowledge of each others value systems (likes,
dislikes, etc.).
Players are rational. (They make logical decisions).
A Fair Division Scheme does NOT guarantee each player a fair share.
(A player may misplay the game.)
It DOES guarantee that it is impossible for other players or bad luck to deny a player
his/her fair share.
3 Continuous Fair Division Schemes
The Divider-Chooser Method (The You cut, I choose
Method. Works only when there are 2 players) Procedure:
- A randomly chosen player (the Divider) divides the set S
into 2 pieces.
- The other player (the Chooser) selects the piece.
The Lone Divider Method (Procedure for 3 players):
A randomly chosen player (the Divider) divides the set S
into 3 pieces s1 , s2 , s3.
The other players (the Choosers) independently list all
acceptable pieces.
Case 1: A player selects more than 1 piece
RESULT: Each player is given an acceptable piece.
Case 2: Choosers select different pieces
RESULT: Each player is given an acceptable piece.
Case 3: Choosers select only one piece but it is the same piece
RESULT: Standoff resolved by randomly giving one of the other two
pieces to the divider, recombining the 2 remaining pieces and applying the Divider-Chooser
Method.
The Last Diminisher Method Procedure:
- Randomly order Players: P1 , P2 ,
, PN.
- P1 cuts a piece.
- P2 either claims a subpiece of P1s
piece (becomes a Diminisher) or passes to contend for a piece of the rest.
- Case 1: P2 becomes a Diminisher.
RESULT: The difference between the 2 claims is put back and P1
becomes a Contender.
Case 2: P2 passes.
RESULT: Play passes to P3.
- Each remaining player, in turn, diminishes or passes. When all have
played, the last diminisher gets his/her piece and departs.
- The process begins again with one less player. When 2 players remain, use
Divider-Chooser.
2 Discrete Fair Division Methods
The Method of Sealed Bids Procedure:
- Each player makes a sealed bid, giving an estimate of the dollar value of
each item. Each players fair share is computed by
dividing the total of the players bids by the # of players.
- Each item goes to the highest bidder for that item (breaking ties in a
pre-determined fashion) and the player adds/subtracts from the pot the difference between
his/her fair share and the total value of the items allocated to that player.
- Any cash left in the pot at the end of this process is divided evenly
among the players.
Necessary conditions:
- Each player must have enough money to play.
- Each player must accept money as a substitute.
- Players must have no useful information about each others
value systems prior to the bidding.
The Method of Markers Procedure (requires many more items than
players):
- The items are linearly ordered.
- Each player independently & secretly divides the items into N
consecutive segments with markers.
- From the set of all players first markers, choose the player with
the first (leftmost) marker and give that player his/her first segment.
Remove all of that players markers.
- Move to the second set of markers & repeat the process above. (Player
with first marker in the second set receives his/her 2nd segment.)
- Continue until each player has a segment. (The last player receives
his/her last segment.)
- Leftovers: If there are more leftovers than players, use the Method of
Markers again. Otherwise, use a lottery.
Necessary conditions:
- There must be many more items than Players.
- Every Player must be able to divide the array of items into segments of
equal value.
Practical way to carry out the Methods of
Markers procedure (using an example)
EXAMPLE: Three players (A, B & C) agree
to divide the 12 items below (numbered 1 - 12). Their markers have already been
placed.
| 1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
11 |
12 |
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A1 |
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A2 C1 |
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B1 |
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C2 |
B2 |
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STEP 1: Put the items in a line and if they are not
already numbered, number them (from left to right).
STEP 2: Put down the markers if that is not already
done.
STEP 3: Create a table with the name of each player
as a row label. Label the columns with the segment numbers that the items will be
divided into (3 players = 3 segments, 4 players = 4 segments, etc.).
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Segment 1 |
Segment 2 |
Segment 3 |
| Player A |
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| Player B |
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| Player C |
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STEP 4: Complete the table by listing each player's
segments as determined by their markers.
| 1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
11 |
12 |
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A1 |
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A2 C1 |
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B1 |
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C2 |
B2 |
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Segment 1 |
Segment 2 |
Segment 3 |
| Player A |
1 |
2-3 |
4-12 |
| Player B |
1-5 |
6-10 |
11-12 |
| Player C |
1-3 |
4-9 |
10-12 |
STEP 5: Give away a first segment to the Player
whose first segment ends first.
Since Player A's first segment ends at 1,
Player A gets his/her first segment. (Item 1)
STEP 6: Mark the Player who got a segment out of
the table and move to the second segment. Give away a second segment to the Player
whose second segment ends first.
Since Player C's second segment ends before all
remaining Players' second segments, Player C gets his/her second segment. (Items 4-9)
STEP 7: Continue this process, giving away segments
until each Player has a segment.
Since Player B is the only Player yet to get a
segment, give Player B his/her third segment. (Items 11-12)
STEP 8: List the set of Leftover Items.
Leftovers: Items 2, 3, 10
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